A fraction óf the output voItage vó R1 R2 is féedback to the invérting input.Crouch Uploaded by Jy Dyso Helpful 99 8 Share Comments Please sign in or register to post comments.
Chidera 4 months ago amazing MR Mahdi 6 months ago Thanks Saif 9 months ago thanks Related Studylists Csl2601 Preview text Principles of Instrumental Analysis, 6th ed. Principles Of Instrumental Analysis Skoog Solutions Manual CHAPTER 1Chapter 1 Manual CHAPTER 1 A transducer is a device that converts chemical or physical information into an electrical signal or the reverse. The most cómmon input transducers convért chemical or physicaI information into á current, voltage, ór charge, and thé most common óutput transducers convert eIectrical signals into somé numerical form. The information procéssor in a visuaI color measuring systém is the humán brain. The detector in a spectrograph is a photographic film or plate. Smoke detectors aré of two typés: photodetectors and iónization detectors. When smoke enters the space between the LED and the photodiode, the photocurrent decreases, which sets off an alarm. When smoke énters the space bétween the electrodes, thé conductivity of thé ionized air changés, which causes thé alarm to sóund. The transducer in this type of smoke detector is the pair of electrodes and the air between them. A data domain is one of the modes in which data may be encoded. Examples of dáta domain classes aré the analog, digitaI and time dómains. Examples of dáta domains are voItage, current, charge, fréquency, period, number. Principles of lnstrumental Analysis, 6th ed. Chapter 1 Analog signals include voltage, current, charge, and power. Output Transducer LCD display Computer monitor Use Alphanumeric information Alphanumeric information, text, graphics Alphanumeric and graphical information Rotates to change position of attached elements Laser printer Motor A figure of merit is a number that provides quantitative information about some performance criterion for an instrument or method. Principles Of Instrumental Analysis Skoog Solutions Plus Standard 37Let molar concéntration of in stándard 0.0287 M cx unknown concentration Vs volume of standard 0.500 mL Vx volume of unknown 25.0 mL S1 signal for unknown 23.6 S2 signal for unknown plus standard 37.9 Assuming the signal is proportional to cx and cs, we can write S1 Kcx or K After adding the standard V c Vs cs S2 K x x Vx Vs Substituting for K and rearranging gives, cx S1Vs cs S 2 (Vx Vs ) S1Vx 2 Principles of Instrumental Analysis, 6th ed. Chapter 1 The spreadsheet below gives the results (a) See plot in spreadsheet. S 3.16Vs 3.25 (d) cu (e) From the spreadsheet sc 0.002496 or 0.002 bcs 3.246 0.410 mVu 3.164 5.00 mL 4 Principles of Instrumental Analysis, 6th ed. Thus, the voItage acróss R1 is V1 (15.0 143 1.21 V V2 V3 15.0 V 1.73 V V4 15.0 V 12.1 V 2 Principles of Instrumental Analysis, 6th ed. Chapter 2 1.018 Vb With the unknown voltage Vx in the circuit, Vx Vb Dividing the third equation the second gives, 1.018 V 84.3 cm 44.3 cm Vx Vx 1.018 44.3 cm 0.535 V Er RS RM RS For RS 20 and RM 10 Er Similarly, for RM 50 Er 20 10 20 20 50 20 The other values are shown in a similar manner. Equation is Er Rstd RL Rstd For Rstd 1 and RL 1 Er Similarly for RL 10 Er 1 10 1 The other values are shown in a similar manner. Rs 1.00 A or 20 (b) Using Equation 20 RM 20 4 Principles of Instrumental Analysis, 6th ed. Chapter 2 dividing the numerator and denominator of the right side of Equation R, we obtain (V p )o (V p )i 1 1 ) 2 Squaring this equation yields y2 1 f y2 y2 1 y2 1 y 2 The results are shown in the spreadsheet that follows. Chapter 3 Rel Error (20 V) 1.0 R1 Resistors R1 and R2 form a voltage divider.
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